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  • CR and Slope

    Perhaps not really a Rules question, but I couldn't find a better place to put it.

    My home course has 3 loops of 9 holes that are combined differently from week to week, 2 loops acting as the 18-hole course, and the last loop playing the part of a 9-hole course for new members (or 'Rabbits' as they are called over here) or members who don't have time to fit in 18 (WHAT?! Not time for 18?! Outrage!! )

    Anyway. The 9-hole loop is often very empty of players, while the 18-hole course is often packed, so sometimes we decide to play the 9-loop twice for 18-holes (it can easily cut an hour off your playing time if you're a 2 ball and nobody is in front of you).

    At the club, we have a handicap conversion table dictating the number of strokes given at the course, but unlike the 18-hole combinations, the 2x9 hole combinations do not have a listed CR and Slope.
    Of course they exist, I just can't find them anywhere.

    Since I'm working on a statistics spreadsheet to monitor my 'improvements' (yeah, I wish), I'd like to have the CR and Slope, so that I could correctly calculate the number of strokes given for any handicap.

    Can I do this, based on the known CR and Slope of the 18-hole combinations?

    The known data are these:

    North Out - East In: CR 72,1 - Slope 126 - Par 72
    West Out - East In: CR 72,9 - Slope 129 - Par 72
    West Out - North In: CR 71,0 - Slope 126 - Par 72

    East Out - East In: Par 72
    West Out - West In: Par 72
    North Out - North In: Par 72

    How can I calculate CR and Slope for East/East, West/West and North/North?

  • #2
    Re: CR and Slope

    Personally, I'd set up the other combinations as Rating 72, slope 126. Three points of slope won't make much of a difference.

    As for actually figuring them out, you'd need the slope and rating of each individual set of 9 - which may or may not be available at the pro shop.

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    • #3
      Re: CR and Slope

      So I can't base the calculation on the knowledge that East/North has a CR of 72,1 and East/West has a CR of 72,9 and from that calculate the CR of East?

      I'm thinking something like the CR of East/North being comprised of half of the CR of East/East and half of the CR of North/North.

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      • #4
        Re: CR and Slope

        If you knew just one of the 9's, I know I could figure the rest, but I just can't seem to figure out how to get a combined 18. From the info you gave, I would suggest the East is most difficult of the 9's and North is the easiest, but I can't give you individual ratings for each 9. Ask the proshop to get this info...

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        • #5
          Re: CR and Slope

          I think I've cracked it ...

          0.5A + 0.5B = 72.1
          A(North)+B(East) = 144,2

          0.5A+0.5C = 71.0
          A+C(West) = 142

          0.5B + 0.5C = 72.9
          B+C = 145.8

          C = 142 - A
          A = 144.2 - B
          C = 145.8 - B
          C = 142 - (144,2 + B)
          145.8 - B = 142 - (144.2 + B)
          145.8 - 142 + 144.2 = 2B
          148 = 2B
          74 = B (East)

          C = 145.8 - 74
          C (West) = 71.8

          A = 144.2 - 74
          A (North)= 70.2


          That makes it all work


          Edited to add:

          Same procedure for slope returns the full data:

          North Out - East In: CR 72,1 - Slope 126 - Par 72
          West Out - East In: CR 72,9 - Slope 129 - Par 72
          West Out - North In: CR 71,0 - Slope 126 - Par 72

          East Out - East In: CR 74,0 - Slope 129 - Par 72
          West Out - West In: CR 71,8 - Slope 129 - Par 72
          North Out - North In: CR 70,2 - 123 - Par 72
          Last edited by Mox; 08-23-2005, 04:06 PM.

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          • #6
            Re: CR and Slope

            I knew there was a way, but it's been too long since i used them last. Once I saw your equation, it made perfect sense. Well done.

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            • #7
              Re: CR and Slope

              That's some good work, Mox.

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              • #8
                Re: CR and Slope

                Originally posted by LowPost42
                That's some good work, Mox.
                Thanks.

                It's been a long time since I've worked on my maths skills. That's the problem with working with computers ... you get used to them knowing the formula already,so you won't have to!

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